Monday, September 29, 2008

Mwahaha! INTRODUCING THE NEW Super Ultra Mega Amazing Blog Post Spectacular as posted by Me!

Haha i just got back from work not too long ago, so naturally I was tired.....

BUT NOW HERE I AM FULLY ENERGIZED AFTER SOME DELICIOUS LIQUID CAFFEINE AND A WHOLE BUNCH OF ENERGY BARS READY TO BLOG!!!! LET'S GET 'ER DONE!!

So basically on Friday we went over something from a while back... That few pages of fill in the blank-y type stuff XD The Chapter 14 Study guide if that helps you at all? Anyways heres how the blanks got filled:

REFLECTION OF WAVES:
The direction of waves moving in two or three dimensions is shown by RAY diagrams. The ray that reaches a barrier is called the INCIDENT ray. The ray that moves back from the barrier is called the REFLECTED ray. The direction of the barrier is shown by a line drawn at a(n) RIGHT ANGLE to the barrier. This line is called the NORMAL. The angle between the INCIDENT ray and the NORMAL is called the angle of incidence. The angle between the REFLECTED ray and the NORMAL is called the angle of reflection. The law of REFLECTION states that the angle of incidence equals the angle of reflection.

REFRACTION OF WAVES:
In water waves, the velocity is SLOWER in shallower water. If the incident ray is parallel to the normal, there is a change in the velocity and WAVELENGTH of the wave. If the incident ray is not parallel to the normal, there is a change in velocity, wavelength, and DIRECTION of the wave. The change in DIRECTION of a wave at the boundary between two media is called refraction.






As for the last par t about
DIFFRACTION AND INTERFERENCE OF WAVES... i only have the answers to the blanks which are: circular, diffraction, wavelength, less, resulting, constructive, destructive


And then TODAY in class we watched a quick video talking about what we were about to do which waaaaaaas.... read through pages 13 -18 as a class in our super special awesome "Grade 11 Physics: Waves in Two Dimensions" booklet/study guide thang XD ( even though i didn't aget a chance to read D= ) Covering such lovely topics as :

DIFFRACTION AROUND A SHARP BARRIER: VARYING WAVELENGTH

DIFFRACTION THROUGH AN OPENING: VARYING SIZE OF OPENING





DIFFRACTION THROUGH AN OPENING: VARYING WAVELENGTHS

CONSTRUCTIVE AND DESTRUCTIVE INTERFERENCE IN TWO DIMENSIONS

NODAL LINES AND THE INTERFERENCE PATTERN

MATHEMATICAL ANALYSIS OF A TWO POINT SOURCE INTERFERENCE PATTERN

AND MANY MANY MANY MORE.... reading this information and learning it will definitely get you 100% on the upcoming test ( though results may vary.) That last bit was a bit of a giant contradiciton, but lets just keep the super physics blog rolling shall we?




The main point of varying wavelengths when it came to sharp barriers was this....


BIGGER WAVELENGTH + SHARP BARRIER = MORE DIFFRACTED (BENT)


Cant put it much more simply than that you guys.




The main point for us to learn out of diffraction through an opening: varying size of opening was fairly simple too....


SMALL OPENING + WAVE = MORE DIFFRACTION (BENDING OF WAVE)


BIG OPENING + WAVE = LESS DIFFRACTION


Once again in Diffraction through an opening, this time the size of wavelngth being the variant factor.... the lesson is simple again, borrowed from our sharp barrier equation i dispalyed earlier:
BIGGER WAVELENGTH + OPENING = MORE DIFFRACTED (BENT), In order for any significant diffraction to be noticed, the ration wavelngth/size of opening should be about (or greater than) 1.




Next we delved into the delightful ( though not as complicated as it appears) world of INTERFERENCE IN 2D!!!








So my badly scanned diagram shows that cosntructive interference can occur between two crests (represented by solid lines) and two troughs (represented by dotted lines). These produce antinodal areas. If you were to look at it from above... the double troughs would be blinding and the crests would be mad dark.... pretty much. Nodal lines are formed where crests and troughs intertwine to form nodes.










Each side of either of the perpindicular bisector of the distance between the two sources has symmetrical nodal/antinodal lines like so:


After this we learned about how we can determine the wavelngth of a wave in 2D using any point on a nodal line and its distance to the vibrating sources via the formula P1S1-P1S2= (n-1/2) wavelength. An example coyuld be that your point was 12 cm away from source one and 6 cm away from source 2. It is located on the 2nd nodal line.
Your equation would work out like this .... 12cm - 6cm = (2-1/2) wavelength
6cm= 1.5 (wavelength)
wavelength = 4cm
Hopefully that makes sense to you guys and sorry about all hte delay on this and what not haha.. as you can tell througout this post I became deadly tired and am now off to a nice rest in a warm comfy bed to prepare for tomorrows wonderful school day. Thank you again to Mrs. K who let me do this thang... I appreciate more than I can say. I truly do. Oooo next scribe.... Sorry bout this but I'm gunna have to pick the_bdl... Please don't hate me :p anyways bye for now fellow physics lovers!

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