Showing posts with label Pretty Mary. Show all posts
Showing posts with label Pretty Mary. Show all posts

Saturday, November 8, 2008

Photoelectric effect & wave-particle duality

Konichiwa!!!
Watakushi-wa Mary Ararcon (Alarcon), desu.

Yesterday (November 7), we did Young's Experiment Problems and "The Current Model of light: Wave- Particle Duality" . We've also tackled pages 22-26 on the green booklet.

If you guys missed yesterday's class, here are the solutions and answers on the experiment problems.......


first, here's the formula:


λ = (X) (d)
L
where:
λ = wavelength
X= distance between adjacent nodal lines
d= separation between slits
L= perpendicular distance from the slits to the screen.

1)
λ = ?
d= 0.0190mm/ 1.9x10 -5m
L= .600m


λ = (0.0211m) (1.9x10 -5m)
.600m

λ = 6.68x10 -10 m/ 668nm

2)
λ = ?
X= 13.2 mm/ 0.0132m
d= 1.90x10 -5 m
L= .600m

λ = (0.0132m) (1.90x10 -5m)
.600m

λ = 4.18x10 -7m/ 4118nm
3)
λ = 596nm/ 5.96x10 -4mm
X=?
d= 1.90x10 -5m/ 0.019mm
L= 600mm

X = (5.96x10 -4mm) ( 600mm)
0.019mm

X = 18.8mm

4)
λ = 632.8nm/6.328x10 -7m)
X= 65.5mm/0.0655m
d= ?
L= 1.000m

d= (6.328x10 -7m) (1.000m)
0.0655m

d=9.66x10 -6 m

5)
λ = ?
X= 55.8mm/0.0558m
d= 9.66x10 -6m
L=1.000m

λ = (0.0558m) (9.66x10 -6m)
1.000m

λ =539nm

6)
λ =542nm/ 5.42x10 -7m
X= 4.00cm/ .04m
d= ?
L= 1.20m

d= (5.42x10 -7m) (1.20m)
.04m

d=1.63x10 -5m

7)
λ = v/f
λ =343m/s
325Hz

λ = 1.055m
X= ?
d= 4.0m
L= 4.5m

X= (1.055m) (4.5m)
4.om

X=1.18m/1.2m










If you are having a trouble reading the duality thighy,, I'm sorry..
I'll just type it for you,,
Particle model:
*Rectilineat Propagation
*Reflection
*Dispersion
*Photoelectric Effect
Both:
*Reflection
*Rectilinear Propagation
*Dispersion
Wave Model:
*RectilinearPropogation
*Reflection
*Refraction
*Dispersion
*Diffraction
*Partial Reflection and Partial Refraction
haish... it's now 6 am and I'm soooooo tired... I still have work tomorrow.. :(
well,,, for the last part,, just read pages 22-26 (green booklet)
Oh,, by the way,, if I'm not mistaken,, Ms. K will not be there on Monday..
Answer the question sheet because we will go over it on Monday..
We also have a test on Thursday...
Okay?!
Ganbatte ne? (Come on)
Aja Aja Fighting!!!!
Yours truly,,
Pretty Mary
and the next scribe is Wonderbread.... I'm sorry,, i don't know who you are. It's just that,,, your code name is cute... So,,, Good Luck...

Sunday, October 26, 2008

October 24, 2008

An nyoung ha se yo… Che irumun Mary Alarcon imnida

Uhm,,,This is my first time here so I guess don’t expect too much from me… : p
Well, last Friday, Ms. K handed back our labs about slopes. Then we corrected the three sheets that she gave last Thursday. Here are the answers:

1st sheet (Speed vs. Time)

Slope = Y2-Y1
X2-X1


A: 10-0 =.48m/s2
22-0

B: 26-0 =1.18m/s2
22-0

C: 37-0 =2.06m/s2
18-0

D: 56-0 =3.5m/s2
16-0

E: 58-0 =6.44m/s2
9-0


2nd sheet (Determining relationships from graphs)

1st Graph

Slope: 2.7 cm/d

Equation: R= (2.7cm/d) t

2nd Graph

Slope: 0.13 m/s

Equation: y = (o.13m/s) t + 5.0m

3rd Graph

Slope: -1.1m/km

Equation: h = (1.1m/km) d + 3.0m

4th Graph

Slope: $23.60/d

Equation: w = (23.60/d) t


3rd Sheet (Interpreting Skills)

1. a.) Acceleration is directly proportional to force
b.) y = kx ; a = kf
c.) Slope Y = (25-0) m/s2
X (40-0) N

=0.625 kg (1/kg)
d.) Inverse of mass
e.) 23N
f.) interpolation
g.) 33m/s2
h.) extrapolation


2. a.) y is proportional to x2
y = kx2
b.) 3-4s
c.) 3-4s



Graph A:


(It is not accurate but it looks the same though. Just ignore the range and units)






Graph B:



(Again just ignore the range and units)









Graph C:












Graph D:












Here are the last questions for this sheet. Try to answer it…..

In which graph is y directly proportional to x?
In which graph does y decreases as x increases?
In which set of data is y inversely proportional to x?
Which graph does not seem to picture a simple relationship?
Which graph has the general equation y = kx2?


And last thing she talked about was the UNIT CONVERSION….seems familiar right??? Well,,, she gave us a worksheet with 10 questions on how to that….

Here it is….

6 km = 6.0 x 10 3 m
4.9 mg = 4.9 x 10 -3 g
7.6 dm = 7.6 x 10 2 mm
32.1 g = 3.21 x 10 3 cg
5.6 x 103 = 5.6 x 10 1 m
760 g = 7.6 x 10 -1 kg
4.50 km2 = 4.5 x 10 6 m2
1.23 g/mL= 1.23 x 10 kg/L
12 km = 1.2 x 10 13 nm
6.4 mg = 6.4 x 10 9 pg

Maybe this table will help you…

­­


So,,, that’s it… Reminder, we have a test on Tuesday…. Okay??!!!! Aja Aja Fighting!!!!